What is the detention time of a 2 million gallon settling basin with a 10,000 gallon/hour water flow?

Detention time, also known as hydraulic retention time, is calculated by dividing the volume of the settling basin by the flow rate of the water entering the basin. In this case, you have a settling basin with a volume of 2 million gallons and a flow rate of 10,000 gallons per hour.

To find the detention time, you can use the formula:

[

\text{Detention Time (hours)} = \frac{\text{Volume of Basin (gallons)}}{\text{Flow Rate (gallons/hour)}}

]

Plugging in the values:

[

\text{Detention Time} = \frac{2,000,000 \text{ gallons}}{10,000 \text{ gallons/hour}} = 200 \text{ hours}

]

To express this in days, you can divide the total hours by the number of hours in a day (24 hours):

[

\text{Detention Time (days)} = \frac{200 \text{ hours}}{24 \text{ hours/day}} \approx 8.33 \text{ days}

]

Rounding gives you approximately 8.3 days. Hence, the calculation shows that the detention time for the