A tank has a liquid level of 18 feet and a diameter of 9 feet. What is the volume of the liquid?

A tank has a liquid level of 18 feet and a diameter of 9 feet. What is the volume of the liquid?

• A. 1144 cu ft
• B. 8561 cu ft
• C. 127 cu ft
• D. 951 cu ft

Answer: (A)

To find the volume of a liquid in a cylindrical tank, the formula used is: \[ \text{Volume} = \pi r^2 h \] where: - \( r \) is the radius of the tank, - \( h \) is the height (or liquid level) of the tank, - \( \pi \) is a constant approximately equal to 3.14159. In this case, the diameter of the tank is 9 feet, therefore the radius \( r \) is half of that: \[ r = \frac{9 \text{ feet}}{2} = 4.5 \text{ feet} \] The height \( h \) of the liquid is given as 18 feet. Now, substituting the values into the volume formula gives: \[ \text{Volume} = \pi (4.5 \text{ feet})^2 (18 \text{ feet}) \] Calculating the radius squared: \[ (4.5)^2 = 20.25 \] Next, we calculate the volume: \[ \text{Volume} = \pi \cdot 20.25 \cdot 18 \] Calculating \( 20.25 \cd

To find the volume of a liquid in a cylindrical tank, the formula used is:

[ \text{Volume} = \pi r^2 h ]

where:

• ( r ) is the radius of the tank,

• ( h ) is the height (or liquid level) of the tank,

• ( \pi ) is a constant approximately equal to 3.14159.

In this case, the diameter of the tank is 9 feet, therefore the radius ( r ) is half of that:

[ r = \frac{9 \text{ feet}}{2} = 4.5 \text{ feet} ]

The height ( h ) of the liquid is given as 18 feet.

Now, substituting the values into the volume formula gives:

[ \text{Volume} = \pi (4.5 \text{ feet})^2 (18 \text{ feet}) ]

Calculating the radius squared:

[ (4.5)^2 = 20.25 ]

Next, we calculate the volume:

[ \text{Volume} = \pi \cdot 20.25 \cdot 18 ]

Calculating ( 20.25 \cd